What are the solution(s) to $5w^2+8w=80$ ?

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Answer 1 · 2018-04-01T12:28:23

$=> w = ( -4 pm 4sqrt 26 ) / 5$

$5w^2+8w = 80$

$=> 5w^2 + 8w - 80 = 0$

Now use the quadratics formula:

$w = ( -b pm sqrt(b^2-4ac) ) / (2a)$

Where $a = 5 , b = 8 , c = -80$

$=> w =( -8 pm sqrt( 8^2 - (4*5*-80 ) )) / (2*5)$

$=> w = ( -4 pm 4sqrt 26 ) / 5$

What are the solution(s) to 5w^2+8w=805w^2+8w=80?