What is int lnx^2 / lnx^3lnx2lnx3?

1 Answer
Nov 14, 2015

intln(x^2)/ln(x^3)dx = (2x)/3 + cln(x2)ln(x3)dx=2x3+c

Explanation:

Well, when integrating you should always have d[arg]d[arg], where [arg] is a variable, it's like int is "(" and that is the ")". It's more important because it tell us with which variable you want us to integrate.

In this case it's pretty clear that's xx but as a general rule it's important to specify.

Anyhow, using the property of logarithms we have

intln(x^2)/ln(x^3)dx = int(2ln(x))/(3ln(x))dx = int(2dx)/3 = (2x)/3 + cln(x2)ln(x3)dx=2ln(x)3ln(x)dx=2dx3=2x3+c

Assuming x in RR, x > 0, x != 1 so as to avoid complex numbers when doing those algebrisms and/or having the function defined in the reals at those points.