What is $\sqrt{2} (5 - \sqrt{2}) ?$ $sqrt2( 5 - sqrt2) ?$

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Answer 1 · 2018-07-26T19:05:54

$5 \sqrt{2} - 2$ $5\sqrt2-2$

Given that

$\sqrt{2} (5 - \sqrt{2})$ $\sqrt2(5-\sqrt2)$

$= \sqrt{2} \cdot 5 - \sqrt{2} \cdot \sqrt{2}$ $=\sqrt2\cdot 5-\sqrt2\cdot \sqrt2$

$= 5 \sqrt{2} - 2$ $=5\sqrt2-2$

Answer 2 · 2018-07-26T22:58:03

$5 \sqrt{2} - 2$ $5sqrt2-2$

We can distribute $\sqrt{2}$ $sqrt2$ to both of the terms in the parenthesis. Recall that $\sqrt{2} \cdot \sqrt{2} = 2$ $sqrt2*sqrt2=2$ . We now have

$5 \sqrt{2} - 2$ $5sqrt2-2$

Hope this helps!

What is √2(5−√2)?sqrt2( 5 - sqrt2) ?