What is the antiderivative of $- 5 e^{x - 1}$ $-5e^(x-1)$ ?

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What is the antiderivative of $- 5 e^{x - 1}$ $-5e^(x-1)$ ?

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Answer 1 · 2015-07-23T19:10:25

I found: $- 5 e^{x - 1} + c$ $-5e^(x-1)+c$

Explanation:

You have:
$\int - 5 e^{x - 1} d x = - 5 \int e^{x - 1} d x =$ $int-5e^(x-1)dx=-5inte^(x-1)dx=$
but $d [(x - 1)] = d x$ $d[(x-1)]=dx$ so you can write:
$- 5 \int e^{x - 1} d (x - 1) =$ $-5inte^(x-1)d(x-1)=$
$= - 5 e^{x - 1} + c$ $=-5e^(x-1)+c$

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What is the antiderivative of $- 5 e^{x - 1}$ $-5e^(x-1)$ ?

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