What is the antiderivative of $π^{x - 1} d x$ $pi^(x-1)dx$ ?

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Answer 1 · 2015-02-19T16:16:11

The answer is: $\frac{π^{x - 1}}{ln π} + c$ $pi^(x-1)/lnpi+c$ .

Since:

$inta^f(x)*f'(x)dx=a^f(x)/lna+c$

Than:

$intpi^(x-1)dx=pi^(x-1)/lnpi+c$ .

What is the antiderivative of pi^(x-1)dxπx−1dxpi^(x-1)dx?