What is the arclength of $f(x)=sqrt(4-x^2)$ in the interval $[-2,2]$ ?

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Answer 1 · 2018-07-10T16:06:08

The arc length is $2pi$ units.

This is a semi circle of radius $2$ . We simply find the perimeter of the full circle of radius $2$ and divide it by $2$ to get our arc length.

$P = 2(2)pi = 4pi$

$P/2 = (4pi)/2 = 2pi$

Therefore the arc length is $2pi$ units.

Hopefully this helps!

What is the arclength of f(x)=sqrt(4-x^2) f(x)=sqrt(4-x^2) in the interval [-2,2][-2,2]?