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What is the conjugate of 3 minus square root of 2?

1 Answer

Alan P. · Konstantinos Michailidis

Sep 29, 2015

It is $3 + \sqrt{2}$ $3+sqrt2$

Explanation:

By definition the conjugate of
$XXX (a + b)$ $color(white)("XXX")(a+b)$ is $(a - b)$ $(a-b)$
and
$XXX (a - b)$ $color(white)("XXX")(a-b)$ is $(a + b)$ $(a+b)$
The term "conjugate" only applies to the sum or difference of two terms.

"3 minus the square root of 2"
means (in algebraic form)
$3 - \sqrt{2}$ $3-sqrt(2)$

Applying the earlier definition with $a = 3$ $a=3$ and $b = \sqrt{2}$ $b=sqrt(2)$
we have
The conjugate of $(3 - \sqrt{2})$ $(3-sqrt(2))$ is $(3 + \sqrt{2})$ $(3+sqrt(2))$

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