What is the derivative of $f(x) = 3x sec^2 x$ ?

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Answer 1 · 2017-12-05T17:33:53

$3sec^2x(1+2xtanx)$

we need the product rule here

$d/(dx)(uv)=v(du)/(dx)+u(dv)/(dx)$

$d/(dx)(3xsec^2x)=sec^2xd/(dx)(3x)+3xd/(dx)(sec^2x)$

$=(sec^2x) xx3+3x xx2secxtancsecx$

$=3sec^2x+6xsec^2xtanx$

$=3sec^2x(1+2xtanx)$

What is the derivative of f(x) = 3x sec^2 x f(x) = 3x sec^2 x?