What is the derivative of ${sec}^{2} (3 x)$ $sec^2(3x)$ ?

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Answer 1 · 2017-05-15T02:57:10

Given: $y = {(sec (3 x))}^{2}$ $y= (sec(3x))^2$

$y'=2[sec(3x)][sec(3x)tan(3x)](3)$

$y'= 6 sec^2 (3x) tan(3x)$

What is the derivative of sec^2(3x)sec2(3x)sec^2(3x)?