What is the derivative of $sec^2 (x) - tan^2 (x)$ ?

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Answer 1 · 2018-06-04T13:48:25

$0$

We want to find $"d"/("d"x)(sec^2x-tan^2x)$ .

This derivative becomes trivial if we note that $sec^2x-tan^2x=1$ .

So

$"d"/("d"x)(sec^2x-tan^2x)="d"/("d"x)1=0$

What is the derivative of sec^2 (x) - tan^2 (x)sec^2 (x) - tan^2 (x)?