What is the derivative of sec(x^2-4)? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Shwetank Mauria Jun 14, 2016 f'(x)=2xsec(x^2-4)tan(x^2-4) Explanation: to find derivative of f(x)=sec(x^2-4), we know that d/(dx) secx=secxtanx Hence f'(x)=sec(x^2-4)tan(x^2-4)xx2x or f'(x)=2xsec(x^2-4)tan(x^2-4) Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 1890 views around the world You can reuse this answer Creative Commons License