What is the derivative of sec x ^5secx5? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer maganbhai P. Mar 6, 2018 5x^4secx^5tanx^55x4secx5tanx5 Explanation: y=sec(x^5)rArr(dy)/(dx)=sec(x^5)tan(x^5)*d/(dx)(x^5)=sec(x^5)tan(x^5)(5x^4)=5x^4secx^5tanx^5y=sec(x5)⇒dydx=sec(x5)tan(x5)⋅ddx(x5)=sec(x5)tan(x5)(5x4)=5x4secx5tanx5 Answer link Related questions What is Derivatives of y=sec(x)y=sec(x) ? What is the Derivative of y=sec(x^2)y=sec(x2)? What is the Derivative of y=x sec(kx)y=xsec(kx)? What is the Derivative of y=sec ^ 2(x)y=sec2(x)? What is the derivative of y=4 sec ^2(x)y=4sec2(x)? What is the derivative of y=ln(sec(x)+tan(x))y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)y=sec2(x)? What is the derivative of y=sec^2(x) + tan^2(x)y=sec2(x)+tan2(x)? What is the derivative of y=sec^3(x)y=sec3(x)? What is the derivative of y=sec(x) tan(x)y=sec(x)tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 4183 views around the world You can reuse this answer Creative Commons License