What is the derivative of $y=tan(x) cot(x)$ ?

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Answer 1 · 2018-04-27T12:20:16

$0$

By trigonometric identities: $cotA=cosA/sinA=1/tanA$

Therefore, $y=tanx(1/tanx)=tanx/tanx=1$
So, $dy/dx=0$

You could try and use product rule as well as the quotient rule for $1/tanx$ and this should give you the same result of $0$ .

Hope this helps!

What is the derivative of y=tan(x) cot(x)y=tan(x) cot(x)?