What is the limit of (sin^4x)/(x^(1/2)) as x approaches infinity? Calculus Limits Limits at Infinity and Horizontal Asymptotes 1 Answer Alan P. Apr 19, 2016 lim_(xrarroo)(sin^4 x)/(x^(1/2)) = 0 Explanation: sin x is limited to the range [-1,+1] rarr sin^4 x is limited to the range [0,1] rarr sin^4 x has an upper limit of 1 while xrarroo x^(1/2) rarr oo as xrarroo Answer link Related questions What kind of functions have horizontal asymptotes? How do you find horizontal asymptotes for f(x) = arctan(x) ? How do you find the horizontal asymptote of a curve? How do you find the horizontal asymptote of the graph of y=(-2x^6+5x+8)/(8x^6+6x+5) ? How do you find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3) ? How do you find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10? How do you find the horizontal asymptote of the graph of y=6x^2 ? How can i find horizontal asymptote? How do you find horizontal asymptotes using limits? What are all horizontal asymptotes of the graph y=(5+2^x)/(1-2^x) ? See all questions in Limits at Infinity and Horizontal Asymptotes Impact of this question 2405 views around the world You can reuse this answer Creative Commons License