What is the limit of (x^3 - 2x +3) / (5-2x^2) as x goes to infinity? Calculus Limits Limits at Infinity and Horizontal Asymptotes 1 Answer Jim H Oct 23, 2015 lim_(xrarroo) (x^3 - 2x +3) / (5-2x^2) = -oo Explanation: lim_(xrarroo) (x^3 - 2x +3) / (5-2x^2) has indeterminate form oo/oo. For all x !=0 we get (x^3 - 2x +3) / (5-2x^2)= (x^2(x-2/x+3/x^2))/(x^2(5/x^2-2)) So lim_(xrarroo) (x^3 - 2x +3) / (5-2x^2) =lim_(xrarroo) (x-2/x+3/x^2)/(5/x^2-2) =oo/-2 = -oo Answer link Related questions What kind of functions have horizontal asymptotes? How do you find horizontal asymptotes for f(x) = arctan(x) ? How do you find the horizontal asymptote of a curve? How do you find the horizontal asymptote of the graph of y=(-2x^6+5x+8)/(8x^6+6x+5) ? How do you find the horizontal asymptote of the graph of y=(-4x^6+6x+3)/(8x^6+9x+3) ? How do you find the horizontal asymptote of the graph of y=3x^6-7x+10/8x^5+9x+10? How do you find the horizontal asymptote of the graph of y=6x^2 ? How can i find horizontal asymptote? How do you find horizontal asymptotes using limits? What are all horizontal asymptotes of the graph y=(5+2^x)/(1-2^x) ? See all questions in Limits at Infinity and Horizontal Asymptotes Impact of this question 10267 views around the world You can reuse this answer Creative Commons License