What is the pH of a $8.7 \cdot 10^{- 12}$ $8.7*10^-12$ $M$ $M$ solution?

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Answer 1 · 2016-07-02T05:11:16

I assume that $[H_{3} O^{+}] = 8.7 \times 10^{- 12}$ $[H_3O^+]=8.7xx10^(-12)$ in water under standard conditions.

In aqeuous solution, $p H = - {log}_{10} [H_{3} O^{+}]$ $pH=-log_10[H_3O^+]$

$=$ $=$ $- {log}_{10} (8.7 \times 10^{- 12})$ $-log_10(8.7xx10^-12)$ $=$ $=$ $- (- 11.06)$ $-(-11.06)$ $=$ $=$ $11.1$ $11.1$

What is the pH of a 8.7⋅10−128.7*10^-12 MM solution?