What is the quadratic formula for $2x^2 - 3x - 5 = 0$ ?

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Answer 1 · 2018-08-04T16:11:26

$x = 5/2$ and $-1$

$2x^2 - 3x - 5 = 0$

The quadratic formula is $x = (-b +- sqrt(b^2 - 4ac))/(2a)$ .

This equation is in standard quadratic form, so we know that:
$a = 2$ , $b = -3$ , and $c = -5$ .

Plug them into the equation and solve for $x$ :
$x = (-(-3) +- sqrt((-3)^2 - 4(2)(-5)))/(2(2))$

$x = (3 +- sqrt(9 + 40))/4$

$x = (3 +- sqrt(49))/4$

$x = (3 +- 7)/4$

$x = 10/4$ and $-4/4$

$x = 5/2$ and $-1$

Hope this helps!

What is the quadratic formula for 2x^2 - 3x - 5 = 02x^2 - 3x - 5 = 0?