What is the standard form of a polynomial $(x-3)^2(x-1)$ ?

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Answer 1 · 2018-03-13T12:26:24

$x^3 - 7x^2 +15x - 9$

First multiply out the squared bracket:
$(x^2 - 6x + 9)(x-1)$

Then multiply out the brackets and simplify:
$x^3 - x^2 -6x^2 +6x +9x - 9$ =
$x^3 - 7x^2 +15x - 9$

What is the standard form of a polynomial (x-3)^2(x-1) (x-3)^2(x-1) ?