What is $x^{\frac{2}{3}} y^{\frac{5}{3}}$ $x^(2/3)y^(5/3)$ in radical form?

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Answer 1 · 2016-07-16T16:42:10

$\sqrt[3]{x^{2} y^{5}}$ $root(3)(x^2y^5)$

By definition: $x^{\frac{p}{q}} = {(\sqrt[q]{x})}^{p}$ $x^(p/q) = (root(q) x)^p$

Both indices have a denominator of 3, which means the cube root.

$x^{\frac{2}{3}} y^{\frac{5}{3}} = \sqrt[3]{x^{2} y^{5}}$ $x^(2/3)y^(5/3) = root(3)(x^2y^5)$

What is x23y53x^(2/3)y^(5/3) in radical form?