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How do you differentiate the following parametric equation: $x (t) = - e^{t} + 4 t, y (t) = 3 t^{2} + 2 t$ $x(t)=-e^t+4t, y(t)= 3t^2+2t$ ?

1 Answer

Nov 21, 2015

$\frac{d y}{d x} = \frac{6 t + 2}{4 - e^{t}}$ $dy/dx = (6t + 2)/(4 - e^t)$

Explanation:

By using the chain rule that is $\frac{d y}{d x} = \frac{d y}{d t} \cdot \frac{d t}{d x}$ $dy/dx = dy/dt * dt/dx$

Hope that helps,
Cheers.

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