A triangle has sides A, B, and C. The angle between sides A and B is (pi)/2π2 and the angle between sides B and C is pi/12π12. If side B has a length of 5, what is the area of the triangle?

1 Answer
Feb 21, 2016

color(blue)(A = 3.34925)A=3.34925

Explanation:

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NOTE: Diagram drawn not to scale

Sorry for my bad drawing :D

Angles in Uppercase Letters (A, B, C)
Sides in Lowercase Letters (a, b, c)

Angle C = pi/2C=π2

Angle A = pi/12A=π12

to convert radian values to degrees, we simply multiply it by 180/pi180π

Angle C = pi/2 * 180/pi = (180cancelpi)/(2cancelpi)

Angle C= 90^o

Angle A = pi/12 * 180/pi = (180cancelpi)/(12cancelpi)

Angle A = 15^o

Side b = 5

we must get the value of Side a to get the area of triangle,

we can use trigonometric functions to get the value of side of the triangle and apply algebraic techniques to find the value of a.

tan 15^o = a/5

5tan15^o = a

a = 5tan15^o

a = 1.3397

Since the formula for Area of Triangle is,

Area = 1/2bh

where b = base can be the side a, and h = height can be the side b.

Plugging All Variables,

Area = 1/2(1.3397)(5)

Area = 3.34925