How do you solve #3( 4y - 1) = 2( 5y + \frac { 1} { 2} )#?
1 Answer
Oct 15, 2016
Explanation:
-
Expand the brackets on both sides
#12y - 3 = 10y + 1# -
Group like terms on different sides of the equation
#12y - 10y = 1 + 3#
#2y = 4# -
Make y the subject
#(2y)/2 = 4/2#
#y = 2#
