Question

How do you differentiate the following parametric equation: `x(t)=-3e^t-4t, y(t)= -5t^2-e^(t)`?

Answer 1

`y'=((-3e^t-4)')/((-10t-e^t)')`

Explanation:

The derivative can be found like this:
`y'=(dy/dt)/(dx/dt)`
Basically, it is the derivatives divided by each other.

`y'=((-3e^t-4t)')/((-5t^2-e^t)')`

`y'=((-3e^t-4)')/((-10t-e^t)')`

Check out the website for a good explanation (much better than mine)

http://tutorial.math.lamar.edu/Classes/CalcII/ParaTangent.aspx