Question

How do you find the area of the triangle given `B=130^circ, a=62, c=20`?

Answer 1

`310sqrt3`

Explanation:

You would apply the formula:

`Area=1/2ac sin hatB`

and get:

`Area=1/cancel2*62*cancel20^10*sin120°`

`=620*sqrt3/2`

`310sqrt3`