How do you find the area of the triangle given $B = 130^{\circ}, a = 62, c = 20$ $B=130^circ, a=62, c=20$ ?

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Answer 1 · 2017-03-22T05:49:07

$310 \sqrt{3}$ $310sqrt3$

You would apply the formula:

$A r e a = \frac{1}{2} a c sin ˆ B$ $Area=1/2ac sin hatB$

and get:

$Area=1/cancel2*62*cancel20^10*sin120°$

$=620*sqrt3/2$

$310sqrt3$

How do you find the area of the triangle given B=130^circ, a=62, c=20B=130∘,a=62,c=20B=130^circ, a=62, c=20?