How do you find the limit of $\frac{sin (x - 2)}{x^{2} - 4}$ $(sin( x - 2)) / (x^2 - 4)$ as x approaches 0?

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Answer 1 · 2017-10-14T15:20:56

$\frac{sin (2)}{4}$ $sin(2)/4$

Let's plug in the value $x = 0$ $x=0$

$lim_(x->0)sin(0-2)/(0-4)$

$=sin(-2)/(-4)= sin(2)/4$

$"or" ~~0 .2273243567$

graph{sin(x-2)/(x^2-4) [-10, 10, -5, 5]}

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