How do you solve $5 x - 4 = 2 x - 13$ $5x - 4= 2x - 13$ ?

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Answer 1 · 2018-03-06T04:14:06

$x = - 3$ $x= -3$

Step 1: Subtract $2 x$ $2x$ from both sides of the equation. Thus, you have

$3 x - 4 = - 13$ $3x-4=-13$

Step 2: Add $4$ $4$ to both sides. You now have

$3 x = - 9$ $3x= -9$

Step 3: Multiply each side by $\frac{1}{3}$ $1/3$ . Thus, you are left with

$x = - 3$ $x= -3$

Answer 2 · 2018-03-06T04:16:59

$x = - 3$ $x=-3$

We know that if we perform the same operation on both sides of the equation, we still get an equality. We start with the equation:

$5 x - 4 = 2 x - 13$ $5x-4=2x-13$

We now try to isolate the $x$ $x$ 's. That is, we want to put all the $x$ $x$ 's on one side:

$5 x - 4 - 2 x = 2 x - 13 - 2 x$ $5x-4-2x=2x-13-2x$

Combine like terms:

$3 x - 4 = - 13$ $3x-4=-13$

We now add $4$ $4$ to both sides:

$3 x - 4 + 4 = - 13 + 4$ $3x-4+4=-13+4$

$3 x = - 9$ $3x=-9$

Finally, we divide both sides by $3$ $3$ :

$\frac{3 x}{3} = \frac{- 9}{3}$ $(3x)/3=(-9)/3$

$x = - 3$ $x=-3$

How do you solve 5x−4=2x−135x - 4= 2x - 13?