How do you solve $11 x - 21 = 8 x + 15$ $11x-21=8x+15$ ?

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Answer 1 · 2018-03-25T19:36:46

$x = 12$ $x = 12$

So you first want to get everything with an $x$ $x$ to one side. So we add $21$ $21$ to both sides:

$11 x - 21 = 8 x + 15 ∣ + 21$ $11x - 21 = 8x + 15 " " | +21$

$11 x = 8 x + 36$ $11x = 8x + 36$

And then subtract $8 x$ $8x$ from both sides:

$11 x = 8 x + 36 ∣ - 8 x$ $11x = 8x + 36" " | -8x$

$3 x = 36$ $3x = 36$

For the final step, we divide by $3$ $3$ on both sides:

$3 x = 36 ∣ \div 3$ $3x = 36" " | div 3$

$x = 12$ $x = 12$

How do you solve 11x-21=8x+1511x−21=8x+1511x-21=8x+15?