How do you solve $28 x - 16 - 16 x = 4 (3 x - 5) + 4$ $28x - 16- 16x = 4( 3x - 5) + 4$ ?

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How do you solve $28 x - 16 - 16 x = 4 (3 x - 5) + 4$ $28x - 16- 16x = 4( 3x - 5) + 4$ ?

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Answer 1 · 2018-04-05T16:59:37

Your answer is 40. Hope it helps

Explanation:

You need to open up the bracket $4 \cdot 3 x = 12 x$ $4*3x=12x$ , and $4 \cdot 5 = 20$ $4*5=20$ , so your equation is $2 x - 16 - 16 x = 12 x - 20 + 4$ $2x- 16 -16x =12x - 20 + 4$ , to collect like terms it will be $28 x - 16 x - 12 x = 20 + 4 + 16$ $28x -16x -12x =20 + 4 + 16$ . Dealing with the $x$ $x$ side of the equation will be $28 x - 16 x$ $28x -16x$ that is equal to $12 x$ $12x$ then $12 x - 12 x = 0$ $12x -12x = 0$ . Now to the second part $20 + 4 = 24$ $20 + 4 =24$ and $24 + 16 = 40$ $24 +16 =40$

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How do you solve $28 x - 16 - 16 x = 4 (3 x - 5) + 4$ $28x - 16- 16x = 4( 3x - 5) + 4$ ?

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How do you solve 28x - 16- 16x = 4( 3x - 5) + 428x−16−16x=4(3x−5)+428x - 16- 16x = 4( 3x - 5) + 4?

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How do you solve $28 x - 16 - 16 x = 4 (3 x - 5) + 4$ $28x - 16- 16x = 4( 3x - 5) + 4$ ?