How do you solve #4x - 11= 5x - 19#?

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Answer 1 · 2018-05-05T01:55:34

#x=8#

In order to solve #4x-11=5x-19#

Begin by using the additive inverse to combine like terms on the opposite sides of the equal sign

#cancel(4x)-11 cancel (-4x)=5x-19 -4x#

#-11 = x-19#

#-11 + 19 = xcancel(-19) cancel(+19)#

#8=x#