Question #99c22

1 Answer
Jim G.
Dec 14, 2016

cosx+sinxcosx+sinx

Explanation:

These 2 functions have color(blue)"standard derivatives"standard derivatives

color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(sinx)=cosx" and " d/dx(cosx)=-sinx)color(white)(2/2)|)))

rArrd/dx(sinx-cosx)=cosx-(-sinx)=cosx+sinx

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