Question #89633

1 Answer
Sep 11, 2016

Integration refers to the inverse process of differentiation. Allow me to illustrate it briefly in the section below.

Explanation:

So example, we have a single valued and differentiable function f(x)f(x)

The differential coefficient or simply the derivative of f(x)f(x) is defined as,

f_1(x) = (df)/dxf1(x)=dfdx which can be defined from the first principle. Where the subscript 1 denotes that it is the first derivative of ff.

Now, let F(x) = f_1(x)F(x)=f1(x) denote the derivative of f(x)f(x)

We define the integral of F(x)F(x) as,

int F(x)dx = f(x) + CF(x)dx=f(x)+C where CC is called the constant of integration.

CC is completely arbitrary and may be defined in some cases by the boundary conditions of the particular problem.

Since, the integral of F(x)F(x) can have an indefinite number of forms just differing by the value of the constant CC, this is called the indefinite integral of F(x)F(x).

So far we are done with the basic definition of integration.

I would like to extend the discussion to the definition of the definite integral.

The definite integral of F(x)F(x) from aa to bb is simple defined as,

int_a^bF(x)dx = [f(x)]_a^bbaF(x)dx=[f(x)]ba

Now, the fundamental theorem of integral calculus states that,

int_a^bF(x)dx =f(b) - f(a)baF(x)dx=f(b)f(a).

There are simple rules for determining the integral of a function. We you are dealing with the indefinite integral, just put a constant and if you're dealing with the definite integral, use the fundamental theorem of integral calculus.

A more rigorous and geometric interpretation of definite integral is provided in most elementary calculus textbooks. Please consult one if you like.