How do you evaluate $intsin(2x)/sin(x)dx$ ?

Question

3778 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-26T04:33:49

Use $sin(2x)=2sin(x)cos(x)$ .

What you need is a double angle trig. identity. Namely, $sin(2x)=2sin(x)cos(x)$ will do the trick.

$intsin(2x)/sin(x)dx=>int(2sin(x)cos(x))/sin(x)dx$

Now you can get $sin(x)$ to cancel, leaving you with:

$int2cos(x)dx=2sin(x)+C$

Good luck!

How do you evaluate intsin(2x)/sin(x)dxintsin(2x)/sin(x)dx?