How do you solve the equation $3sqrt(x) = x- 4$ ?

Question

1545 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-27T22:29:00

$x= 16$

$3sqrt(x) = x - 4$

$(3sqrt(x))^2 = (x- 4)^2$

$9(x) = x^2 - 8x+ 16$

$0 = x^2 - 17x + 16$

$0 = (x - 16)(x - 1)$

$x = 16 and 1$

Check:

$3sqrt(16) + 3 =^? 16 - 1$

$3(4) + 3 = 15" "color(green)(√)$

$3sqrt(1) + 3 =^? 1 - 1$

$3 + 3 != 0" "color(red)(xx)$

Hopefully this helps!

How do you solve the equation 3sqrt(x) = x- 43sqrt(x) = x- 4?