Question #b4941

1 Answer
Nov 10, 2017

The quotient rule is:

(d(u/v))/dx = (u'v - uv')/v^2

In this case, u = x^2+x^2tan^2(x) and v = sec^2(x), then

u' = 2x + 2xtan^2(x)+ 2x^2tan(x)sec^2(x) and v' = 2tan(x)sec^2(x)

Substituting these values into the quotient rule:

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = ((2x + 2xtan^2(x)+ 2x^2tan(x)sec^2(x))sec^2(x) - (x^2+x^2tan^2(x))(2tan(x)sec^2(x)))/sec^4(x)

A common factor of sec^2(x)/sec^2(x) becomes 1:

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = ((2x + 2xtan^2(x)+ 2x^2tan(x)sec^2(x))- (x^2+x^2tan^2(x))(2tan(x)))/sec^2(x)

The term - (x^2+x^2tan^2(x))(2tan(x)) can be written as -2x^2tan(x)sec^2(x)):

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = ((2x + 2xtan^2(x)+ 2x^2tan(x)sec^2(x)) -2x^2tan(x)sec^2(x))/sec^2(x)

The last two terms in the numerator sum to 0:

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = (2x + 2xtan^2(x))/sec^2(x)

Use the identity 1+ tan^2(x) = sec^2(x):

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = 2x sec^2(x)/sec^2(x)

sec^2(x)/sec^2(x) becomes 1:

(d((x^2+x^2tan^2(x))/sec^2(x)))/dx = 2x

It would have been better to avoid using the quotient rule by making the substitution, 1+ tan^2(x) = sec^2(x), at the start:

(x^2+x^2tan^2(x))/sec^2(x) = x^2sec^2(x)/sec^2(x) = x^2

(d(x^2))/dx = 2x