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Question #c7e5d

1 Answer

A. S. Adikesavan

Feb 17, 2017

$sec^2(x-pi/4))$

Explanation:

$f=(cosx(tanx-1))/(cosx(tanx+1))$

$=(tanx-tan(pi/4))/(1+tanxtan(pi/4))$

$=tan(x-pi/4)$ . So,

$f'=sec^2(x-pi/4)(x-pi/4)'=sec^2(x-pi/4)$

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