Question

Question #881a0

Answer 1

`h=-4/7`

Explanation:

To eliminate the fractions in the equation, multiply ALL terms on both sides by the `color(blue)"lowest common multiple"` (LCM) of the denominators 4, 2 and 8

the LCM of 4, 2 and 8 is 8

`rArr(cancel(8)^2xx(5h)/cancel(4)^1)+(cancel(8)^4xx1/cancel(2)^1)=(cancel(8)^1xx(3h)/cancel(8)^1)`

`rArr10h+4=3hlarrcolor(red)"no fractions"`

subtract 3h from both sides.

`10h-3h+4=cancel(3h)cancel(-3h)`

`rArr7h+4=0`

subtract 4 from both sides.

`7hcancel(+4)cancel(-4)=0-4`

`rArr7h=-4`

divide both sides by 7

`(cancel(7) h)/cancel(7)=(-4)/7`

`rArrh=-4/7" is the solution"`