Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #5c90e

1 Answer

Mar 1, 2017

$int_0^pi sin^2(7x) dx = pi/2$

Explanation:

$int_0^pi sin^2(7x) dx = 1/2 int_0^pi (1-cos(14x))dx$

$int_0^pi sin^2(7x) dx = 1/2 int_0^pi dx - 1/2 int 1/14cos(14x)d(14x)$

$int_0^pi sin^2(7x) dx = [x/2 - 1/28 sin(14x)]_0^pi$

$int_0^pi sin^2(7x) dx = (pi/2 - 1/28 sin(14pi)) - (0/2 -1/28sin(0))$

$int_0^pi sin^2(7x) dx = pi/2$

Related questions

See all questions in Integrals of Trigonometric Functions

Impact of this question

1295 views around the world

You can reuse this answer
Creative Commons License