Solve? $\frac{1}{1 - x} = \frac{3}{x - 3}$ $1/(1-x)=3/(x-3)$

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Answer 1 · 2017-03-05T11:36:46

$x = \frac{3}{2}$ $x=3/2$

$\frac{1}{1 - x} = \frac{3}{x - 3}$ $1/(1-x)=3/(x-3)$

Let's cross multiply:

$x - 3 = 3 (1 - x)$ $x-3=3(1-x)$

$x - 3 = 3 - 3 x$ $x-3=3-3x$

$4 x = 6$ $4x=6$

$x = \frac{3}{2}$ $x=3/2$

Check the answer:

$\frac{1}{1 - (\frac{3}{2})} = \frac{3}{(\frac{3}{2}) - 3}$ $1/(1-(3/2))=3/((3/2)-3)$

$\frac{1}{- \frac{1}{2}} = \frac{3}{- \frac{3}{2}}$ $1/(-1/2)=3/(-3/2)$

$\frac{1}{1} \times (- \frac{2}{1}) = \frac{3}{1} \times (- \frac{2}{3})$ $1/1xx(-2/1)=3/1xx(-2/3)$

$- 2 = - 2000 \sqrt{}$ $-2=-2 color(white)(000)color(green)sqrt$

Solve? 11−x=3x−31/(1-x)=3/(x-3)