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What is the derivative of $\frac{1 - sin x}{cos x}$ $(1-sinx)/cosx$ ?

1 Answer

Mar 20, 2017

$\frac{d y}{d x} = sec x tan x - {sec}^{2} x$ $dy/dx = secxtanx - sec^2x$

Explanation:

We have:

$y = \frac{1 - sin x}{cos x}$ $y = (1-sinx)/cosx$
$\ \ = 1/cosx - sinx/cosx$

Differentiating wrt $x$ we get:

$dy/dx = secx - tanx$
$\ \ \ \ \ = secxtanx - sec^2x$

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