Solve? $\frac{1}{5} + \frac{1}{2} = 4 (\frac{4}{5 x - 5})$ $1/5+1/2=4(4/(5x-5))$

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Answer 1 · 2017-04-01T06:16:20

$x = \frac{195}{35} = \frac{39 \times 5}{7 \times 5} = \frac{39}{7}$ $x=195/35=(39xx5)/(7xx5)=39/7$

I read this as:

$\frac{1}{5} + \frac{1}{2} = 4 (\frac{4}{5 x - 5})$ $1/5+1/2=4(4/(5x-5))$

I'll first combine the left hand side and multiply through on the right hand side:

$\frac{1}{5} (\frac{2}{2}) + \frac{1}{2} (\frac{5}{5}) = 4 (\frac{4}{5 x - 5})$ $1/5(2/2)+1/2(5/5)=4(4/(5x-5))$

$\frac{2}{10} + \frac{5}{10} = \frac{16}{5 x - 5}$ $2/10+5/10=16/(5x-5)$

$\frac{7}{10} = \frac{16}{5 x - 5}$ $7/10=16/(5x-5)$

Let's now cross multiply:

$7 (5 x - 5) = 10 \times 16$ $7(5x-5)=10xx16$

$35 x - 35 = 160$ $35x-35=160$

$35 x = 195$ $35x=195$

$x = \frac{195}{35} = \frac{39 \times 5}{7 \times 5} = \frac{39}{7}$ $x=195/35=(39xx5)/(7xx5)=39/7$

Solve? 15+12=4(45x−5)1/5+1/2=4(4/(5x-5))