A triangle has sides A, B, and C. Sides A and B have lengths of 1 and 4, respectively. The angle between A and C is #(5pi)/24# and the angle between B and C is # (13pi)/24#. What is the area of the triangle?

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Answer 1 · 2017-06-13T12:58:44

The area of the triangle is #=sqrt2=1.41u^2#

The angle between #A# and #C# is

#=pi-(5/24pi+13/24pi)#

#=pi-18/24pi#

#=6/24pi=1/4pi#

The area of the triangle #DeltaABC# is

#=1/2*A*B*sin(1/4pi)#

#=1/2*1*4*sqrt2/2#

#=sqrt2#

#=1.41#