Question

A triangle has sides A, B, and C. The angle between sides A and B is `(3pi)/4` and the angle between sides B and C is `pi/12`. If side B has a length of 13, what is the area of the triangle?

Answer 1

Area of the triangle is `30.93` Sq units

Explanation:

The angle between sides B & C is `/_A=pi/12=180/12=15^0`
The angle between sides A & B is `/_C=3*pi/4=3*180/4=135^0`
So Angle `/_B=180-(135+15)=30^0` Using sine law we get `B/sin B=A/sinAor 13/sin30=A/sin15 or A=13*sin15/sin30=6.73` Area `= (A.B.sinC)/2 = (13*6.73*sin135)/2=30.93` sq.units