Question

A triangle has sides A, B, and C. The angle between sides A and B is `(5pi)/12` and the angle between sides B and C is `pi/6`. If side B has a length of 2, what is the area of the triangle?

Answer 1

The area of this triangle is 1.

Explanation:

In this triangle the angle between `A` and `C` is `pi-pi/6-(5pi)/12=(5pi)/12` so we have an iscoseles triangle, thus `C=2`.

The area is `P=1/2 BCsin(angle(B,C))=1/2*2*2*sin(pi/6)=1`.