What is the derivative of $y=e^(3-2x)$ ?

Question

14777 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-09-07T11:26:20

By Chain Rule,
$y'=-2e^{3-2x}$ .

Recall:
Exponential Rule: $(e^x)'=e^x$
Chain Rule: $[f(g(x))]'=f'(g(x))cdot g'(x)$

Since $f(x)=e^x$ and $g(x)=3-2x$ , we have
$y'=e^{3-2x}cdot(-2)=-2e^{3-2x}$

What is the derivative of y=e^(3-2x)y=e^(3-2x) ?