How do you find the derivative of $y=e^(2x)$ ?

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Answer 1 · 2014-09-08T00:59:16

By Chain Rule,
$y'=2e^{2x}$

Recall:
$(e^x)'=e^x$
Chain Rule: $[f(g(x))]'=f'(g(x))cdot g'(x)$

In the posted problem,
$f(x)=e^x$ and $g(x)=2x$
By taking the derivative,
$f'(x)=e^x$ and $g'(x)=2$

By Chain Rule,
$y'=e^{2x}cdot2=2e^{2x}$

How do you find the derivative of y=e^(2x)y=e^(2x)?