How do you find the derivative of #y=e^(1/x)#?
1 Answer
Jul 30, 2014
#y'=-e^(1/x)/(x^2)# Explanation :
Using Chain Rule,
Suppose,
#y=e^f(x)# then,
#y'=e^f(x)*f'(x)# Similarly following for the
#y=e^(1/x)#
#y'=e^(1/x)*(1/x)'#
#y'=e^(1/x)*(-1/x^2)#
#y'=-e^(1/x)/(x^2)#
