Question

Given `(x^2-9)/(x-3)` how do you find the limit as x approaches 3?

Answer 1

First notice that `(x^2-9)/(x-3)=[(x-3)(x+3)]/(x-3)=(x+3)`

Hence `lim_(x->3) (x^2-9)/(x-3)=lim_(x->3) (x+3)=6`