How can you derive the quotient rule?

1 Answer
Aug 19, 2014

This can be proven fairly quickly, assuming knowledge of prior subjects such as the product rule and chain rule. Suppose f(x) = (u(x))/(v(x)). As we know that all of our equations are in terms of x, henceforth x will be omitted from the steps below. Note however that it is still present as the variable for the functions.

(d/dx)f = (d/dx)u/v

Then via our definition f= u/v we get u= f*v. Differentiating this via use of the product rule nets us...

u' = f'*v + f*v'

Now as we isolate f' on its own side...

f'= [u'-f*v']/(v)

Recalling that f=u/v this becomes...

f' = [u' - (u/v)*v']/v

And by multiplying both the numerator and denominator by v we get...

f' = [u'*v - u*v']/[v^2]

Or, by showing x again...

f'(x) = [u'(x)*v(x) - u(x)*v'(x)]/(v(x))^2