How do you differentiate $\frac{1}{1 + x^{2}}$ $1/(1+x^2)$ ?

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Answer 1 · 2016-09-12T12:01:57

I found: $- \frac{2 x}{{(1 + x^{2})}^{2}}$ $-(2x)/(1+x^2)^2$

Try this:
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Answer 2 · 2016-09-12T12:03:49

$- \frac{2 x}{{(1 + x^{2})}^{2}}$ $-(2x)/(1+x^2)^2$

$y'=((1+x^2)^(-1))'=-(1+x^2)(-2)*(1+x^2)'=-(2x)/(1+x^2)^2$

How do you differentiate 1/(1+x^2)11+x21/(1+x^2)?