How do you differentiate f(x)=x^2/sin x?

1 Answer
Feb 14, 2017

f'(x)=(2xsinx-x^2cosx)/(sin^2x)

Explanation:

differentiate f(x) using the color(blue)"quotient rule"

"Given "f(x)=(g(x))/(h(x))" then"

color(red)(bar(ul(|color(white)(2/2)color(black)(f'(x)=(h(x)g'(x)-g(x)h'(x))/(h(x))^2)color(white)(2/2)|)))

"here "g(x)=x^2rArrg'(x)=2x

"and "h(x)=sinxrArrh'(x)=cosx

rArrf'(x)=(2xsinx-x^2cosx)/(sin^2x)